Unable to passing arguments to jar launcher into shell script

i've the following problem, these is my shell script: #!/bin/bash CONFIG_FOLDER=./config JAVA_HOME=/home/lorenzo/Downloads/jdk1.7.0_25/bin CHARSET=utf8 $JAVA_HOME/java -DconfigFolder=$CONFIG_FOLDER -jar com.lorenzo.myapp.jar When I run the script I get the following error: /java: not foundmyscript.sh: 5: myscritp.sh: /home/lorenzo/Downloads/jdk1.7.0_25/bin Any idea? P.S myscript.sh is the posted script. EDIT: I've found a partial solution: #!/bin/bash CONFIG_FOLDER=./config export PATH=$PATH:/home/user/jdk1.7/bin java -DconfigFolder=$CONFIG_FOLDER -jar com.lorenzo.myapp.jar But now, I've another problem: the value of $CONFIG_FOLDER is empty when i run the script. Why?
Did you try changing the order between -D and -jar? Like this: $JAVA_HOME/java -jar -DconfigFolder=$CONFIG_FOLDER com.lorenzo.myapp.jar

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