Given char *p = "string", why does modification result in undefined behavior?

char *p = "string literal"; p[0] = 'S'; char a[] = "string literal"; a[0] = 'S'; 1. What is the main difference between these two? 2. What really happens in the memory when these two are defined? 3. Why modifying the first one results in undefined behavior? 4. I read somewhere that first one may store in read-only memory; my question is: how does that happen?

以上就是Given char *p = "string", why does modification result in undefined behavior?的详细内容,更多请关注web前端其它相关文章!

赞(0) 打赏
未经允许不得转载:web前端首页 » CSS3 答疑

评论 抢沙发

  • 昵称 (必填)
  • 邮箱 (必填)
  • 网址

前端开发相关广告投放 更专业 更精准

联系我们

觉得文章有用就打赏一下文章作者

支付宝扫一扫打赏

微信扫一扫打赏