How can you code the C "&&" operator in x86?

How can I code the C '&&' operator in x86? For example: int a = ... int b = ... int c = a && b; What would be the equivalent of the last line in x86? EDIT: I want to do the above without any jumps. EDIT: g++ generates this, but I don't understand it: testl %edi, %edi setne %dl xorl %eax, %eax testl %esi, %esi setne %al andl %edx, %eax
There are no jumps required for that example; the code in question has a very direct translation to assembly. @Ivan has your answer for you already.

以上就是How can you code the C "&&" operator in x86?的详细内容,更多请关注web前端其它相关文章!

赞(0) 打赏
未经允许不得转载:web前端首页 » CSS3 答疑

评论 抢沙发

  • 昵称 (必填)
  • 邮箱 (必填)
  • 网址

前端开发相关广告投放 更专业 更精准

联系我们

觉得文章有用就打赏一下文章作者

支付宝扫一扫打赏

微信扫一扫打赏