Why does scanf() need "%lf" for doubles, when printf() is okay with just "%f"?

Why is it that `scanf()` needs the `l` in "`%lf`" when reading a `double`, when `printf()` can use "`%f`" regardless of whether its argument is a `double` or a `float`? Example code: double d; scanf("%lf", &d); printf("%f", d);
I don't understand what you mean by POINTER here. In scanf we only pass &variable (i.e)address so where is the pointer

以上就是Why does scanf() need "%lf" for doubles, when printf() is okay with just "%f"?的详细内容,更多请关注web前端其它相关文章!

赞(0) 打赏
未经允许不得转载:web前端首页 » CSS3 答疑

评论 抢沙发

  • 昵称 (必填)
  • 邮箱 (必填)
  • 网址

前端开发相关广告投放 更专业 更精准

联系我们

觉得文章有用就打赏一下文章作者

支付宝扫一扫打赏

微信扫一扫打赏